toJson method

  1. @override
Map<String, Object> toJson({
  1. ClientUriConverter? clientUriConverter,
})

Returns a JSON presentation of the object.

Implementation

@override
Map<String, Object> toJson({ClientUriConverter? clientUriConverter}) {
  var result = <String, Object>{};
  result['initialProblems'] = initialProblems
      .map(
        (RefactoringProblem value) =>
            value.toJson(clientUriConverter: clientUriConverter),
      )
      .toList();
  result['optionsProblems'] = optionsProblems
      .map(
        (RefactoringProblem value) =>
            value.toJson(clientUriConverter: clientUriConverter),
      )
      .toList();
  result['finalProblems'] = finalProblems
      .map(
        (RefactoringProblem value) =>
            value.toJson(clientUriConverter: clientUriConverter),
      )
      .toList();
  var feedback = this.feedback;
  if (feedback != null) {
    result['feedback'] = feedback.toJson(
      clientUriConverter: clientUriConverter,
    );
  }
  var change = this.change;
  if (change != null) {
    result['change'] = change.toJson(clientUriConverter: clientUriConverter);
  }
  var potentialEdits = this.potentialEdits;
  if (potentialEdits != null) {
    result['potentialEdits'] = potentialEdits;
  }
  return result;
}