fromJson method

  1. @override
UnspeccedGetSuggestedUsersOutput fromJson(
  1. Map<String, dynamic> json
)

Implementation

@override
UnspeccedGetSuggestedUsersOutput fromJson(Map<String, dynamic> json) {
  return UnspeccedGetSuggestedUsersOutput.fromJson(
    translate(json, UnspeccedGetSuggestedUsersOutput.knownProps),
  );
}