dpftrs function
void
dpftrs()
Implementation
void dpftrs(
final String TRANSR,
final String UPLO,
final int N,
final int NRHS,
final Array<double> A_,
final Matrix<double> B_,
final int LDB,
final Box<int> INFO,
) {
final A = A_.having(offset: zeroIndexedArrayOffset);
final B = B_.having(ld: LDB, offset: zeroIndexedMatrixOffset);
const ONE = 1.0;
bool LOWER, NORMALTRANSR;
// Test the input parameters.
INFO.value = 0;
NORMALTRANSR = lsame(TRANSR, 'N');
LOWER = lsame(UPLO, 'L');
if (!NORMALTRANSR && !lsame(TRANSR, 'T')) {
INFO.value = -1;
} else if (!LOWER && !lsame(UPLO, 'U')) {
INFO.value = -2;
} else if (N < 0) {
INFO.value = -3;
} else if (NRHS < 0) {
INFO.value = -4;
} else if (LDB < max(1, N)) {
INFO.value = -7;
}
if (INFO.value != 0) {
xerbla('DPFTRS', -INFO.value);
return;
}
// Quick return if possible
if (N == 0 || NRHS == 0) return;
// start execution: there are two triangular solves
if (LOWER) {
dtfsm(TRANSR, 'L', UPLO, 'N', 'N', N, NRHS, ONE, A, B, LDB);
dtfsm(TRANSR, 'L', UPLO, 'T', 'N', N, NRHS, ONE, A, B, LDB);
} else {
dtfsm(TRANSR, 'L', UPLO, 'T', 'N', N, NRHS, ONE, A, B, LDB);
dtfsm(TRANSR, 'L', UPLO, 'N', 'N', N, NRHS, ONE, A, B, LDB);
}
}