dtptrs function
void
dtptrs()
Implementation
void dtptrs(
final String UPLO,
final String TRANS,
final String DIAG,
final int N,
final int NRHS,
final Array<double> AP_,
final Matrix<double> B_,
final int LDB,
final Box<int> INFO,
) {
final AP = AP_.having();
final B = B_.having(ld: LDB);
const ZERO = 0.0;
bool NOUNIT, UPPER;
int J, JC;
// Test the input parameters.
INFO.value = 0;
UPPER = lsame(UPLO, 'U');
NOUNIT = lsame(DIAG, 'N');
if (!UPPER && !lsame(UPLO, 'L')) {
INFO.value = -1;
} else if (!lsame(TRANS, 'N') && !lsame(TRANS, 'T') && !lsame(TRANS, 'C')) {
INFO.value = -2;
} else if (!NOUNIT && !lsame(DIAG, 'U')) {
INFO.value = -3;
} else if (N < 0) {
INFO.value = -4;
} else if (NRHS < 0) {
INFO.value = -5;
} else if (LDB < max(1, N)) {
INFO.value = -8;
}
if (INFO.value != 0) {
xerbla('DTPTRS', -INFO.value);
return;
}
// Quick return if possible
if (N == 0) return;
// Check for singularity.
if (NOUNIT) {
if (UPPER) {
JC = 1;
for (INFO.value = 1; INFO.value <= N; INFO.value++) {
if (AP[JC + INFO.value - 1] == ZERO) return;
JC += INFO.value;
}
} else {
JC = 1;
for (INFO.value = 1; INFO.value <= N; INFO.value++) {
if (AP[JC] == ZERO) return;
JC += N - INFO.value + 1;
}
}
}
INFO.value = 0;
// Solve A * x = b or A**T * x = b.
for (J = 1; J <= NRHS; J++) {
dtpsv(UPLO, TRANS, DIAG, N, AP, B(1, J).asArray(), 1);
}
}