deserialize method

Implementation

void deserialize(XmlElement xml) {
  // set busy
  busy = true;

  // inner scope
  if (!isNullOrEmpty(Xml.get(node: xml, tag: 'scope'))) {
    _subscope = Scope(parent: scope, id: Xml.get(node: xml, tag: 'scope'));
  }

  // retain a pointer to the xml
  element = xml;

  // properties
  debug = Xml.get(node: xml, tag: 'debug');
  datasource = Xml.get(node: xml, tag: 'data');

  // register a listener to the datasource if specified
  IDataSource? source = scope?.getDataSource(datasource);
  source?.register(this);

  // we first sort the elements moving vars and datasources to the top of the
  // deserialization sequence in order to avoid excessive deferred bindings
  var elements = xml.children.whereType<XmlElement>().toList();
  if (elements.length > 1) {
    var topmost = elements
        .where((element) => _topmost.contains(element.name.toString()))
        .toList();
    if (topmost.isNotEmpty && topmost.length != elements.length) {
      elements.removeWhere((element) => topmost.contains(element));
      elements.insertAll(0, topmost);
    }
  }

  // deserialize children
  children?.clear();
  for (var element in elements) {
    // deserialize the model
    var model = WidgetModel.fromXml(this, element);

    if (model != null)
    {
      // add model to the datasource list
      if (model is IDataSource) {
        (datasources ??= []).add(model as IDataSource);
      }

      // add model to the child list
      // in cases like camera, it is both a viewable widget as well
      // as a data source.
      if (model is! IDataSource || model is ViewableWidgetMixin) {
        (children ??= []).add(model);
      }
    }
  }

  // set idle
  busy = false;
}