distinct method

Iterable<T> distinct()

Returns a new lazy Iterable containing only distinct elements.

This method filters the current iterable, ensuring that only unique elements are included in the resulting iterable. The order of elements is preserved.

  • Returns: A new lazy Iterable containing only distinct elements.

  • Examples:

    Iterable<int> numbers = [1, 2, 2, 3, 4, 4, 5];
Iterable<int> distinctNumbers = numbers.distinct();
print(distinctNumbers); // [1, 2, 3, 4, 5]

Note: This method does not modify the original iterable. It creates a new lazy iterable with distinct elements from the original iterable while preserving their order.

Implementation

Iterable<T> distinct() sync* {
  var existing = HashSet<T>();
  for (var current in this) {
    if (existing.add(current)) {
      yield current;
    }
  }
}