openUrl method

  1. @override
Future<void> openUrl({
  1. required String url,
})
override

Opens a given URL in the default web browser or app.

This function attempts to launch the specified URL using the system's default browser or an appropriate app (e.g., YouTube app for a YouTube link).

Parameters:

  • url (required): The URL to be opened.

Returns:

  • A Future that resolves to true if the URL was successfully opened.
  • Returns false if the URL could not be opened.

Example Usage:

await openUrl(url: 'https://flutter.cn');

This method should be implemented to provide actual functionality.

Implementation

@override
Future<void> openUrl({required String url}) async {
  await ThanPkg.android.app.openUrl(url: url);
}